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Simple Interest Exercise 2

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Simple Interest 2

  • This online quiz will test your knowledge of Simple Interest in Quantitative Aptitude.
  • This Online Test is useful for academic and competitive exams.
  • Multiple answer choices are given for each question in this test. You have to choose the best option.
  • After completing the test, you can see your result.
  • There is no negative marking for wrong answers.
  • There is no specified time to complete this test.

A man received ₹12000 as Puja Bonus. He invested a part of it at 5% per annum and the remaining at 6% per annum on simple interest being allowed in each case. The total interest earned by him in 4 years is ₹2580. The sum invested at 5% per annum is

Let the sum invested at 5% be ₹x.

According to the question,

interest-32441.png

= 2580

interest-32435.png

interest-32429.png

interest-32423.png

⇒ x = ₹7500.

The simple interest accrued on a sum of certain principal is ₹1,200 in four year at the rate of 8% p.a. What would be the simple interest accrued on thrice of that principal at the rate of 6% p.a in 3 year?

Principal

= interest-34597.png

= ₹3750

Simple interest on thrice that principal

= interest-34591.png

= ₹2025

Mr. Sane invested a total amount of ₹16,500 for two years in two schemes A and B with rate of simple interest 10 p.c.p.a. and 12 p.c.p.a. respectively. If the total amount of interest earned was ₹3,620, what was the amount invested in scheme B?

% interest on total amount per annum

= interest-34585.png

Now, use Alligation method.

interest-34579.png

Hence, ratio of amount invested in schemes A and B

= interest-34572.png

Hence, amount invested in B

=interest-34566.png= ₹8000

Out of a certain sum, ⅓rd is invested at 3%, ⅙th at 6% and the rest at 8%. If the simple interest for 2 years from all these investments amounts to ₹600, find the original sum.

Rest part

interest-34560.png

Rate % per annum on total sum

interest-34554.png

∴ interest-34548.png

The simple interest on a sum of money is ¹⁄₉ of the principal and the number of years is equal to the rate % p.a. The rate % p.a. is

Here interest-34542.pngand R = T

interest-34536.png

interest-34530.png

A sum of money lent out at simple interest amounts to ₹720 after 2 years and to ₹1,020 after a further period of 5 years. Find the sum and the rate %.

S.I. for 5 years

= ₹(1020 –720) = ₹300

SI. for 2 years

= interest-34512.png

∴ Principal = ₹(720 – 120) = ₹600

Now, P = 600, T = 2, S.I. = 120

∴ interest-34506.png

A sum was put at simple interest at a certain rate for 4 years Had it been put at 2% higher rate, it would have fetched ₹56 more. Find the sum.

Difference in S.I.

interest-34499.png

⇒ interest-34493.png (Since R₁ – R₂ = 2)

⇒ interest-34487.png

Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond five years. If he pays a total interest of ₹11,400 at the end of nine years, how much money did he borrow?

Let the sum borrowed be x. Then,

interest-34481.png

interest-34475.png

interest-34468.png

Hence, sum borrowed = ₹12,000.

Two equal sums of money were invested, one at 4% and the other at 4.5%. At the end of 7 years, the simple interest received from the latter exceeded to that received from the former by ₹31.50. Each sum was :

Difference of S.I.

= interest-34462.png

Let each sum be ₹x. Then

interest-34456.png

⇒ interest-34450.png

⇒ x = ₹900

A sum of ₹725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of ₹362.50 more is lent but at the rate twice the former. At the end of the year, ₹33.50 is earned as interest from both the loans. What was the original rate of interest?

Let the original rate be R%.

Then, new rate = (2R)%.

interest-34444.png

interest-34438.png

interest-34432.png

A father left a will of ₹68,000 to be divided between his two sons aged 10 years and 12 years such that they may get equal amount when each attains the age of 18 years If the money is reckoned at 10% p.a., find how much each gets at the time of the will.

Let one gets = ₹x,

then, second gets = ₹(68,000 – x)

Given : A₁ = A₂

interest-34426.png

interest-34418.png

interest-34412.png

interest-34406.png

∴ second gets = ₹36,000

If there are three sum of money P,Q and R so that P is the simple interest of Q and Q is the simple interest of R, rate % and time are same in each case, then the relation of P, Q and R is given by

interest-32490.png

interest-32484.png

∴ Q² = PR.

A milk man borrowed ₹2,500 from two money lendeRs For one loan, he paid 5% p.a. and for the other, he paid 7% p.a. The total interest paid for two years was ₹275. How much did he borrow at 7% rate?

Let he borrowed at 5% = ₹x

∴ He borrowed at 7% = ₹(2500 – x)

Now I₁ + I₂ = 275

interest-32700.png

⇒ 10x + 14 (2500 – x) = 27500

⇒ 4x = 35000 – 27500 = 7500

⇒ x = ₹1875

∴ Sum borrowed at 7% rate

= 2500 – 1875 = ₹625

Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years If the total interest paid by him at the end of eleven years is ₹8160, how much money did he borrow?

Let the sum be ₹x. Then,

interest-32694.png

⇒ 18 x + 45x + 39x = (8160 × 100)

⇒ 102x = 816000

⇒ x = 8000.

Mr. Thomas invested an amount of ₹13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be ₹3508, what was the amount invested in Scheme B?

Let the sum invested in Scheme A be ₹x and that in Scheme B be ₹(13900 – x).

Then, interest-32688.png

⇒ 28x – 22x = 350800 – (13900 × 22)

⇒ 6x = 45000

⇒ x = 7500.

So, sum invested in Scheme B

= ₹(13900 – 7500) = ₹6400.

An amount of ₹1,00,000 is invested in two types of shares. The first yields an interest of 9% p.a. and the second, 11% p.a. If the total interest at the end of one year is 9¾% , then the amount invested in each share was:

Let the sum invested at 9% be ₹x and that invested at 11% be ₹(100000 – x).

Then, interest-32682.pnginterest-32676.png

interest-32670.png

⇒ 2x = (1100000 – 975000) = 125000

⇒ x = 62500.

∴ Sum invested at 9% = ₹62500.

Sum invested at 11%

= ₹(100000 – 62500) = ₹37500.

David invested certain amount in three different Schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was ₹3200 and the amount invested in Scheme C was 150 % of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?

Let x, y and z be the amounts invested in schemes A, B and C respectively. Then,

interest-32664.png

⇒ 10x + 12y + 15z = 320000 ... (i)

Now, z = 240% of y

= interest-32658.png ... (ii)

And, z = 150% of x

= interest-32652.png

interest-32646.png ... (iii)

From (i), (ii) and (iii), we have :

16y + 12y + 36y = 320000

⇒ 64y = 320000

⇒ y = 5000.

∴ Sum invested in Scheme B = ₹5000.

Rajesh gave ₹1200 on loan. Some amount he gave at 4% per annum simple interest and remaining at 5% per annum simple interest. After two years, he got ₹110 as interest. Then the amounts given at 4% and 5% per annum simple interest are, respectively :

Let the amount of the loss at 4% per annum be ₹x.

Amount given at 5% per annum = ₹(1200 – x)

Now, interest-32603.png

⇒ x = ₹500

And, (1200 – x)

= 1200 – 500 = ₹700

Divide ₹2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is:

Let the parts be x, y and [2379 – (x + y)].

interest-32597.png

interest-32591.png

interest-32585.png

But x + y +z = 2379.

interest-32579.png

⇒ 1380 k + 1320 k + 1256 k

= 2379 × 11 × 23 × 6

interest-32573.png

interest-32567.png

Hence, the first part is ₹828.

Simple interest on a certain amount is ⁹⁄₁₆ of the principal. If the numbers representing the rate of interest in percent and time in years be equal, then time, for which the principal is lent out, is:

interest-33190.png

interest-33184.png

Now check your Result..

Your score is

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