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Mixture and Alligation Exercise 1

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Mixture and Alligation 1

  • This online quiz will test your knowledge of Mixture and Alligation in Quantitative Aptitude.
  • This Online Test is useful for academic and competitive exams.
  • Multiple answer choices are given for each question in this test. You have to choose the best option.
  • After completing the test, you can see your result.
  • There is no negative marking for wrong answers.
  • There is no specified time to complete this test.

Gold is 19 times as heavy as water and copper is 9 times heavy. In what ratio must these metals be mixed so that the mixture may be 15 times as heavy as water?

By the rule of alligation, we have

mixture-and-alligation-q-45447.png

∴ required ratio

mixture-and-alligation-q-45441.png

In a mixture of 45 litres, the ratio of milk and water is 3 : 2. How much water must be added to make the ratio 9 : 11?

Quantity of milk

= mixture-and-alligation-q-45483.png

Quantity of water

= mixture-and-alligation-q-45477.png

Let x litres of water be added to make the ratio 9 : 11.

∴ mixture-and-alligation-q-45470.png

⇒ 18 + x = 33

⇒ x =15 litres

In a mixture of 45 litres, the ratio of milk and water is 4 : 1. How much water must be added to make the mixture ratio 3 : 2?

Quantity of milk

= mixture-and-alligation-q-45508.png = 36 litres

Quantity of water

= mixture-and-alligation-q-45502.png = 9 litres

Let x litres of water be added to make the ratio 3 : 2

Then, mixture-and-alligation-q-45496.png

⇒ 72 = 27 + 3x

⇒ x = 15 litres

A mixture (40 litres) contains tonic and water in the ratio 3 : 1. To make the ratio 7 : 2, how much additional amount of water is required?

Tonic = 30 litres, Water = 10 litres

Let x litres of water be added, then

mixture-and-alligation-q-45521.png

⇒ 70 + 7x = 80 + 2x

⇒ 5x = 10

⇒ x = 2 litres.

An alloy contains copper and zinc in the ratio 5 : 3 and another alloy contains copper and tin in the ratio 8 : 5. If equal weights of both the alloys are melted together, then the weight of tin in the resulting alloy per unit will be:

The first type of alloy does not contain tin. Second type alloy contains tin. Therefore, quantity of tin in 2 units of the resulting alloy = ⁵⁄₁₃

⇒ Quantity of tin in 1 unit of the resulting alloy

= mixture-and-alligation-q-45567.png

In three vessels, the ratio of water and milk is 6 : 7, 5 : 9 and 8 : 7, respectively. If the mixtures of the three vessels are mixed together, then what will be the ratio of water and milk?

WaterMilkTotal
1st vessel6713
2nd vessel5914
3rd vessel8715

LCM of 13, 14 & 15 = 2730

Increase value of total to 2730 as follows.

1st vessel126014702730
2nd vessel97517552730
3rd vessel145612742730
Total369144998190

∴ Required ratio

mixture-and-alligation-q-45585.png

Alternate method is dividing options by 13, 14 & 15.

A jar of oil was four fifths full. When six bottles of oil were taken out and four bottles of oil were poured into, it was three fourths full. How many bottles of oil were contained by the jar?

Let the capacity of the jar be of x bottles.

Since 6 bottles were taken out from jar and 4 bottles of oil poured into it

∴ 2 bottles were taken out

Therefore, we have

⇒ mixture-and-alligation-q-45737.png

⇒ mixture-and-alligation-q-45731.png

⇒ x = 40

A cane contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the cane is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the cane initially?

Suppose the cane initially contains 7x and 5x litres of mixtures A and B respectively.

Quantity of A in mixture left

=mixture-and-alligation-q-46045.png

Quantity of B in mixture left

=mixture-and-alligation-q-46039.png

mixture-and-alligation-q-46033.png

⇒ 252 x – 189 = 140 x + 147

⇒ 112 x = 336

⇒ x = 3.

So, the cane contained 21 litres of A.

A vessel is fully filled with a special liquid. Four litres of liquid is drawn out of this vessel and is replaced with water. If the ratio of the special liquid to the water becomes 1: 2, then what is the capacity the vessel?

Let capacity of the vessel be x litres.

Therefore,mixture-and-alligation-q-46008.png

∴ x = 6

Two equal glasses filled with mixtures of alcohol and water in the proportions of 2 : 1 and 1 : 1 respectively were emptied into third glass. What is the proportion of alcohol and water in the third glass?

Alcohol in 1st glass = ⅔;

water in 1st glass = ⅓

Alcohol in 2nd glass = ½ ;

water in 2nd glass = ½

∴ In 3rd glass,

mixture-and-alligation-q-46001.png

water =mixture-and-alligation-q-45995.png

∴ Required ratio

mixture-and-alligation-q-45988.png

A mixture of Nitric acid and Sulfuric acid is taken in the ratio of 1 : 2 and another mixture of the same is taken in the ratio 2 : 3. How many parts of the two mixtures must be taken to attain a new mixture consisting of Nitric acid and Sulfuric acid in the ratio of 3 : 5?

By alligation rule

mixture-and-alligation-q-46107.png

∴ The ratio in which the two are to be mixed is

mixture-and-alligation-q-46101.png : mixture-and-alligation-q-46095.png

= 3 : 5

Several litres of acid were drawn off from a 54 litre vessel, full of acid and equal amount of water was added. Again the same volume of the mixture was drawn off and replaced by water. As a result now, the vessel contained 24 litres of pure acid. How much of the acid was drawn off initially?

Let a container contains x units of liquid and y units of liquid is taken out from it. If this operation is repeated n times, then the final quantity of the liquid in the container is

mixture-and-alligation-q-46089.png.

∴ From this equation, we have

mixture-and-alligation-q-46083.png

(y = amount of acid initially drawn off)

⇒ mixture-and-alligation-q-46076.png

⇒ mixture-and-alligation-q-46070.png

⇒ mixture-and-alligation-q-46064.png

⇒ y = 18 litres

Two vessels contain mixtures of milk and water in the ratio of 8 : 1 and 1 : 5 respectively. The contents of both of these are mixed in a specific ratio into a third vessel. How much mixture must be drawn from the second vessel to fill the third vessel (capacity 26 gallons) completely in order that the resulting mixture may be half milk and half water?

Let x gallons of first mixture be mixed with y gallons of second mixture.

MilkWater
x gallons (1st)mixture-and-alligation-q-46472.pngmixture-and-alligation-q-46466.png
y gallons (2nd)mixture-and-alligation-q-46460.pngmixture-and-alligation-q-46454.png
Third vesselmixture-and-alligation-q-46448.pngmixture-and-alligation-q-46442.png

Since the third vessel contains half milk and half water,

mixture-and-alligation-q-46436.png

⇒ 16x + 3y = 2x + 15y

⇒ 16x – 2x = 15y – 3y

mixture-and-alligation-q-46430.png

Hence mixture-and-alligation-q-46424.png

= 14 gallons

A container contains 40 litres of milk. From this container, 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

Let a container contains x units of liquid and y units of liquid is taken out from it. If this operation is repeated n times, then the final quantity of the liquid in the container is

mixture-and-alligation-q-46418.png

= 29.16 litres

Three containers A, B and C are having mixtures of milk and water in the ratio 1 : 5, 3 : 5 and 5 : 7, respectively. If the capacities of the containers are in the ratio 5 : 4 : 5, then find the ratio of the milk to the water if the mixtures of all the three containers are mixed together.

Ratio of milk in the containers are,

mixture-and-alligation-q-46412.png

and the ratio of water in the containers are,

mixture-and-alligation-q-46406.png

Ratio of mixture of milk and water in the containers

=mixture-and-alligation-q-46399.png

= 106 : 230 = 53 : 115

Tea worth ₹126 per kg and ₹135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth ₹153 per kg, then the price of the third variety per kg is:

Let the third type of tea is priced at ₹x per kg. Also suppose that the three types of tea mixed together are ℓ, ℓ and 2 kg,respectively.

Now, mixture-and-alligation-q-46711.png

⇒ mixture-and-alligation-q-46705.png

⇒ 261 + 2x = 612

⇒ mixture-and-alligation-q-46699.png

How much water must be added to 60 litres of milk at 1½ litres for ₹20 so as to have a mixture worth ₹10⅔ a litre?

C.P. of 1 litre of milk

=mixture-and-alligation-q-47106.png

mixture-and-alligation-q-47100.png

∴ Ratio of water and milk

=mixture-and-alligation-q-47093.png

= 8 : 32 = 1 : 4.

∴ Quantity of water to be added to 60 litres of milk

=mixture-and-alligation-q-47087.pnglitres

= 15 litres.

Pure milk costs ₹3.60 per litre. A milkman adds water to 25 litres of pure milk and sells the mixture at ₹3 per litre. How many litres of water does he add?

In mixture,

mixture-and-alligation-q-47069.png

Since in every 5 litres of milk, he adds 1 litre of water.

∴ In every 25 litres of milk, he adds 5 litres of water.

Sameer bought 10 kg of tea at ₹45 per kg and 8 kg at ₹50 per kg. He mixed both the brands and sold it at a total profit of ₹32. What was the selling price per kg of the mixture?

C. P. of mixture of 18 kg

= 10 × 45 + 8 × 50 = ₹850

∴ S. P. = C. P. + profit

= 850 + 32 = ₹882

∴ S. P. = ₹882 for 18 kg

∴ S. P. for 1 kg

mixture-and-alligation-q-47063.png =₹49

A mixture consists of 15 parts of coffee, purchased at ₹2.10 per kg and 1 part of chicory, purchased at 98 paise per kg. If it is sold at ₹2.25 per kg, what profit would be made on the sale of 5 quintals?

C. P. of mixture

mixture-and-alligation-q-47443.png

= ₹2.03 per kg

Profit on 1 kg of mixture

= ₹(2.25 – 2.03) = ₹0.22

∴ profit on 5 quintals mixture

= 0.22 × 500 = ₹110

[since 1 quintal = 100 kg]

Now check your Result..

Your score is

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