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- Most Important Multiple Choice Questions
- Online Time Speed and Distance Exercise with Correct Answer Key and Solutions
- Useful for all Competitive Exams

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- Question 1 of 15
##### 1. Question

A train does a journey without stoppage in 8 hours, if it had travelled 5 km/h faster, it would have done the journey in 6 hours 40 minutes. Find its original speed.

##### Hint

Let original speed = S km/h

Here, distance to be covered is constant

- Question 2 of 15
##### 2. Question

Without stoppages, a train travels certain distance with an average speed of 80 km/h, and with stoppages, it covers the same distance with an average speed of 60 km/h. How many minutes per hour the train stops?

##### Hint

Due to stoppages, it covers 20 km less.

Time taken to cover

= 15 min

- Question 3 of 15
##### 3. Question

A train running between two stations A and B arrives at its destination 10 minutes late when its speed is 50 km/h and 50 minutes late when its speed is 30km/h. What is the distance between the stations A and B?

##### Hint

Let the distance between the two stations be x km.

Then,

⇒

⇒ x = 50 km

Thus distance between the station A and B = 50 km

- Question 4 of 15
##### 4. Question

A train with 90 km/h crosses a bridge in 36 seconds. Another train 100 metres shorter crosses the same bridge at 45 km/h. What is the time taken by the second train to cross the bridge?

##### Hint

Let the length of the first train be x metres and the length of the bridge be y metres.

∴ The first train running with the speed of 90 km/h crosses the bridge by covering a distance of (x + y) meters in 36 seconds i.e. The first train crosses the bridge in 36 seconds running with the speed of 25 meters per second.

∴ x + y = 36 × 25 = 900

The second train crosses the bridge by covering a distance of [(x – 100) + y] meters with the speed of 45 km/h, i.e. with the speed of 12½ metres per second.

Since x + y = 900, therefore the second train crosses the bridge by covering a distance of 800 meters @ 12½ meters per second, i.e. the second train crosses the bridge in

= seconds.

- Question 5 of 15
##### 5. Question

A man started running at a distance of 225 metre from the train. If the speed of the man is 6 km/h, then how much time should the train wait so that the man will be just able to catch it?

##### Hint

- Question 6 of 15
##### 6. Question

A man sitting in a train which is travelling at 50 kmph observes that a goods train, travelling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.

##### Hint

Relative speed

= kmph

= 112 kmph.

∴ Speed of goods train

= (112 – 50) kmph = 62 kmph.

- Question 7 of 15
##### 7. Question

Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:

##### Hint

Let us name the trains as A and B. Then,

(A’s speed) : (B’s speed)

=

- Question 8 of 15
##### 8. Question

A train 75 metres long overtook a man who was walking at the rate of 6 km/h and passed him in 18 seconds. Again, the train overtook a second person in 15 seconds. At what rate was the second person travelling?

##### Hint

Let actual speed of train

Then,

⇒ ST = 21 km/h

Now, let speed of second man = Sm

⇒

- Question 9 of 15
##### 9. Question

A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

##### Hint

Speed of train relative to jogger

= (45 – 9) km/h = 36 km/h

Distance to be covered = (240 + 120)

m = 360 m.

∴ Time taken = ³⁶⁰⁄₁₀ sec = 36 sec.

- Question 10 of 15
##### 10. Question

Two trains are running at 40 km/h and 20 km/h respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?

##### Hint

Relative speed = (40 – 20) km/h

Length of faster train

= .

- Question 11 of 15
##### 11. Question

Two trains, 130 and 110 metres long, while going in the same direction, the faster train takes one minute to pass the other completely. If they are moving in opposite direction, they pass each other completely in 3 seconds. Find the speed of trains.

##### Hint

Let speed of trains be S₁ m/s and S₂ m/s.

Then, … (i)

and … (ii)

on solving (i) and (ii), we get

S₁ = 42 m/s , S₂ = 38 m/s

- Question 12 of 15
##### 12. Question

Local trains leave from a station at an interval of 15 minutes at a speed of 16 km/h. A man moving from opposite side meets the trains at an interval of 12 minutes. Find the speed of the man.

##### Hint

Let speed of man = S km/h. Then,

Distance covered in 15 min = Distance covered in 12 min

⇒ 16 + S = 20 ⇒ S = 4 km/h

- Question 13 of 15
##### 13. Question

A goods train leaves a station at a certain time and at a fixed speed. After 6 hours, an express train leaves the same station and moves in the same direction at a uniform speed of 90 kmph. This train catches up the goods train in 4 hours Find the speed of the goods train.

##### Hint

Let the speed of the goods train be x kmph.

Distance covered by goods train in 10 hour

= Distance covered by express train in 4 hour

∴ 10x = 4 × 90 or x = 36.

So, speed of goods train = 36 kmph.

- Question 14 of 15
##### 14. Question

Excluding stoppages, the speed of a train in 45 km/h and including stoppages, it is 36 km/h. For how many minutes does the train stop per hour?

##### Hint

Due to stoppages the train travels

(45 – 36) = 9 km less in an hour than it could have travelled without stoppages.

Thus train stops per hour for

min.

- Question 15 of 15
##### 15. Question

Bombay Express left Delhi for Bombay at 14 : 30 hrs, travelling at a speed of 60 kmph and Rajdhani Express left Delhi for Bombay on the same day at 16 : 30 hrs, travelling at a speed of 80 kmph. How far away from Delhi will the two trains meet?

##### Hint

Here, distance to be covered is constant.

Suppose they meet x hour after 14.30 hr

Then, 60x = 80 (x – 2) or x = 8.

∴ Required distance = (60 × 8) km = 480 km.