Which is the least number that must be subtracted from 1856, so that the remainder when divided by 7, 12 and 16 will leave the same remainder 4?
Suppose least number be x
1856 - x = n(LCM of 7, 12, 16) + 4
⇒ 1856 -x = n (336) + 4
we should take n = 5 so that n(336) is nearest to 1856 and n (336)< 1856
1856 - x = 1680 + 4 = 1684
x = 1856 - 1684 = 172