Let the kerosene level of cylindrical jar be h.
Now, Volume of conical vessel
= ⅓ πr²h
Since, radius (r)
= 2 cm and height(h) = 3cm of conical vessel.
∴ Volume = ⅓ π × 4 × 3 = 4 π
Now, Volume of cylindrical jar = πr²h
= π (2)²h = 4πh
Now, Volume of conical vessel = Volume of cylindrical Jar
⇒ 4 π = 4 πh
⇒ h = 1cm
Hence, kerosene level in Jar is 1 cm.